OK found a reference. He was contesting his phone bill. So he sent this, because he felt he owed nothing. So the answer is 0.
Here is a quote.
"CalcMajor January 27, 2007 at 5:01 pm
noob mathematicians ;-p the total is essentially 0.
e^([pi]i) = -1 just like ln(-1)=[pi]i
i, indicates an imaginary number which has a few different calculations than real numbers. You can do it by hand, or just say ’screw it’ and use a TI-83 or equivalent.
∑1/2^n = 1
Even though beginners will translate it as .999… that number is a fallacious number, and is thus translated as 1. (Just like 2/3 is equal to .666…, 3/3 = .999… AND 1)
And finally, when dealing with money, anything less than a cent, can NOT be rounded up to a cent. It is in fact rounded down.
Plan and simple, he gave them a check for nothing… and is refusing to pay his bill."
5 comments:
Does anyone know what that series sum is? I could probably go through my old math books, but I'm feeling lazy right now.
Pretty sure it has to be 42 for all the right reasons.
This made it's rounds 3 years ago. Will find out if I still have the answer.
OK found a reference. He was contesting his phone bill. So he sent this, because he felt he owed nothing. So the answer is 0.
Here is a quote.
"CalcMajor
January 27, 2007 at 5:01 pm
noob mathematicians ;-p the total is essentially 0.
e^([pi]i) = -1
just like ln(-1)=[pi]i
i, indicates an imaginary number which has a few different calculations than real numbers. You can do it by hand, or just say ’screw it’ and use a TI-83 or equivalent.
∑1/2^n = 1
Even though beginners will translate it as .999… that number is a fallacious number, and is thus translated as 1. (Just like 2/3 is equal to .666…, 3/3 = .999… AND 1)
And finally, when dealing with money, anything less than a cent, can NOT be rounded up to a cent. It is in fact rounded down.
Plan and simple, he gave them a check for nothing… and is refusing to pay his bill."
smedrock - "The Geek King is dead! Long Live The Geek King!" Where do you find this shit? You rawk.
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